Mohammed Shami took one wicket for 28 runs in 3 overs against Chennai Super Kings.
IPL 2025: Sunrisers Hyderabad defeated Chennai Super Kings by 5 wickets in their last match. CSK, batting first, were all out for 154 in 19.5 overs at home. Hyderabad’s team chased the target in 18.4 overs and achieved a spectacular victory.
Mohammed Shami’s performance in the match against Chennai was good, he took one wicket for 28 runs in 3 overs. However, during this spell, Shami has achieved a big feat. The fast bowler has left behind players like Bhuvneshwar Kumar, Lasith Malinga.
Shami did a great feat
In the match against Chennai Super Kings, Mohammed Shami created history by dismissing Sheikh Rashid on the first ball of the first over of the innings. He has become the only bowler to take a wicket on the first ball of the innings four times in IPL. He left behind bowlers like Bhuvneshwar Kumar, Umesh Yadav, Trent Boult, Praveen Kumar and Lasith Malinga, who have taken a wicket on the first ball of the innings thrice.
This is how Sheikh Rashid was out
Mohammad Shami bowled a good length ball which got bounce. Rashid tried to play with hard hands but got an outside edge and Abhishek Sharma stationed at slip took a brilliant catch. And Rashid had to return to the pavilion on a golden duck.
Talking about the performance of Sunrisers Hyderabad and Chennai Super Kings in the ongoing IPL, the journey so far has been like a nightmare for both the teams. CSK is currently at the 10th position in the points table with only two wins in 9 matches. Whereas Hyderabad is at the 8th position with 6 points and three wins in 9 matches. Looking at the feat that Royal Challengers Bangalore had performed last time, both the teams would not want to accept defeat. It remains to be seen how the teams of Hyderabad and Chennai perform in the upcoming matches.
